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Given a list of non negative integers, arrange them such that they form the largest number.
For example, given [3, 30, 34, 5, 9]
, the largest formed number is 9534330
.
Note: The result may be very large, so you need to return a string instead of an integer.
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考点就是comparator的用法,这里注意用(s1+s2).compareTo(s2+s1) 来排序{12, 121}的结果是{121, 12}
排序完之后组成String要从面开始append,当然如果用(s2+s1).compareTo(s1+s2)排序的顺序会反过来
还有就是注意都是0这个conor case,比如一串0,0,0,0,0, 应该返回“0”, 而不是“00000”
public class Solution {
public String largestNumber(int[] nums) {
if(nums == null || nums.length == 0)
return "";
String[] strs = new String[nums.length];
for(int i = 0; i < nums.length; i++){
strs[i] = String.valueOf(nums[i]);
}
Arrays.sort(strs, new Comparator<String>(){
@Override
public int compare(String s1, String s2){
return (s1 + s2).compareTo(s2 + s1);//从小到大
}
});
StringBuilder sb = new StringBuilder();
for(int i = strs.length - 1; i >= 0; i--){
sb.append(strs[i]);
}
return sb.charAt(0) == '0' ? "0" : sb.toString();
}
}