LeetCode279 完美平方数

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, …) which sum to n.

Example 1:

Input: n = 12
Output: 3
Explanation: 12 = 4 + 4 + 4.
Example 2:

Input: n = 13
Output: 2
Explanation: 13 = 4 + 9.

class Solution {
    public int numSquares(int n) {
        int[] dp = new int[n+1];
        dp[0] = 0;
        for(int i = 1; i <= n; i++){
            int j = 1;
            int min = Integer.MAX_VALUE;
            while(i - j*j >= 0){
                min = Math.min(dp[i - j*j] + 1, min);
                j++;
            }
            dp[i] = min;
        }
        return dp[n];
    }
}

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转载自blog.csdn.net/fruit513/article/details/85991209