PAT (Advanced Level) Practice A1028 List Sorting （25 分）(C++) (甲级)

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1028 List Sorting （25 分）
Excel can sort records according to any column. Now you are supposed to imitate this function.

Input Specification:

Each input file contains one test case. For each case, the first line contains two integers N (≤10
​5
​​ ) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student’s record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

Output Specification:

For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID’s; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID’s in increasing order.

Sample Input 1:

3 1
000007 James 85
000010 Amy 90
000001 Zoe 60
Sample Output 1:

000001 Zoe 60
000007 James 85
000010 Amy 90
Sample Input 2:

4 2
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 98
Sample Output 2:

000010 Amy 90
000002 James 98
000007 James 85
000001 Zoe 60
Sample Input 3:

4 3
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 90
Sample Output 3:

000001 Zoe 60
000007 James 85
000002 James 90
000010 Amy 90

using namespace std;
#include<algorithm>
#include<iostream>
#include<cstdio>
#include<cstring>

typedef struct Student
{
    char ID[10];
    char name[10];
    int grade;
}Student;

Student S[100010] = {0};

int N = 0, C = 0;

bool cmp(Student A, Student B)
{
    if(C == 1) return strcmp(A.ID, B.ID) < 0;//按ID升序
    if(C == 2)//按name非降序
    {
        if(strcmp(A.name, B.name)) return strcmp(A.name, B.name) < 0;//两字符串相等时strcmp返回0
        else return strcmp(A.ID, B.ID) < 0;//字典序小于返回值为负，否则为正
    }
    if(A.grade != B.grade) return A.grade < B.grade;//按成绩非降序
    else strcmp(A.ID, B.ID) < 0;
}

int main()
{
    scanf("%d %d", &N, &C);
    for(int i=0; i<N; i++)
    {
        scanf("%s %s %d", S[i].ID, S[i].name, &S[i].grade);
    }
    sort(S, S+N, cmp);
    for(int i=0; i<N; i++)
    {
        printf("%s %s %d\n", S[i].ID, S[i].name, S[i].grade);
    }
    return 0;
}