Python-剑指Offer(九):打印输出大数1-n

问题描述

输入n,按顺序打印出1到最大的那位十进制数。比如输入3,打印出1、2、3到最大3位数999。

算法思路

int型存储有限,long型存储也不够。设置数组,以进位形式,输出结果。
python代码:

def print_num(n):
    n_array = (n+1) * [0]
    while n_array[n] == 0:
        i = 0
        if n_array[i] <= 9:
            n_array[i] += 1
        while n_array[i] == 10 and i+1 < len(n_array):
            n_array[i] = 0
            n_array[i+1] += 1
            i += 1

        i = n-1
        if n_array[n] == 0:
            while i >= 0:
                print(n_array[i], end='')
                i -= 1
            print('')

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转载自blog.csdn.net/qq_35134080/article/details/88014999
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