PAT A1061 Dating

水题，没神马好说的，注意审题和条件的寻找；

#include <iostream>
#include <stdio.h>
#include <string.h>
 
using namespace std;
 
char day[][4] = {"MON", "TUE", "WED", "THU", "FRI", "SAT", "SUN"};
 
int main()
{
    char str1[61], str2[61], str3[61], str4[61];
    scanf("%s%s%s%s", str1, str2, str3, str4);
    int len1, len2, len3, len4;
    len1 = strlen(str1); len2 = strlen(str2);
    len3 = strlen(str3); len4 = strlen(str4);
    int idx1=0, d=0, h=0, m=0;
    // 寻找d
    for(; idx1<len1&&idx1<len2; idx1++) {
        if(str1[idx1]>='A' && str1[idx1]<='G') {
            if(str1[idx1] == str2[idx1]) {
                d = (str1[idx1]-'A')+1; break;
            }
        }
    }
    // 寻找h
    for(idx1++; idx1<len1&&idx1<len2; idx1++) {
        if((str1[idx1]>='0'&&str1[idx1]<='9')||(str1[idx1]>='A'&&str1[idx1]<='N')) {
            if(str1[idx1] == str2[idx1]) {
                if(str1[idx1]>='0'&&str1[idx1]<='9') {
                    h = (str1[idx1]-'0');
                } else {
                    h = (str1[idx1]-'A') + 10;
                }
                break;
            }
        }
    }
    // 寻找m
    for(int i=0; i<len3&&i<len4; i++) {
        if((str3[i]>='a'&&str3[i]<='z')||(str3[i]>='A'&&str3[i]<='Z')) {
            if(str3[i] == str4[i]) {
                m = i; break;
            }
        }
    }
    printf("%s %02d:%02d", day[d-1], h, m);
    return 0;
}