回溯--- Permutations

46.Permutations (Medium)](https://leetcode.com/problems/permutations/description/)

[1,2,3] have the following permutations:
[
  [1,2,3],
  [1,3,2],
  [2,1,3],
  [2,3,1],
  [3,1,2],
  [3,2,1]
]

题目描述:

  给定一个数组,返回数组中元素所能组成的所有序列。

思路分析:

  排列问题,可以用回溯的思路进行解决

代码:

public List<List<Integer>>permute(int []nums){
    List<List<Integer>>res=new ArrayList<>();
    if(nums==null||nums.length=0)
        return res;
    List<Integer>list=new ArrayList<>();
    boolean []visited=new boolean[nums.length];
    backtracking(nums,visited,res,list);
    return res;
}
public void backtracking(int[]nums,boolean []visited,List<List<Integer>>res,List<Integer>list){
    if(list.size()==nums.length){
        res.add(new ArrayList<>(list));//重新构造一个List
        return;
    }
    for(int i=0;i<nums.length;i++){
        if(visited[i]==true)
            continue;
        visited[i]=true;
        list.add(nums[i]);
        backtracking(nums,visited,res,list);
        list.remove(list.size()-1);
        visited[i]=false;
    }
}

猜你喜欢

转载自www.cnblogs.com/yjxyy/p/11112928.html