代码:
count = 0 for i in range(2,101): for j in range(2,i): if i % j == 0: break else: print(i,end=" ") count += 1 print("") print("2-100之间的素数有{}个".format(count))
结果:
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 2-100之间的素数有25个