js 原生方法获取所有兄弟节点

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        <title>js 原生方法获取所有兄弟节点</title>
    </head>

    <body>
        <ul>
            <li id="first">1</li>
            <li>2</li>
            <li>3</li>
        </ul>
        <script type="text/javascript">
            //方法一:
            //            function sibling(elem) {
            //                var r = [];
            //                var n = elem.parentNode.firstChild;
            //                for(; n; n = n.nextSibling) {
            //                    if(n.nodeType === 1 && n !== elem) {
            //                        r.push(n);
            //                    }
            //                }
            //                return r;
            //            }
            //方法二
            function sibling(elm) {
                var a = [];
                var p = elm.parentNode.children;
                for(var i = 0, pl = p.length; i < pl; i++) {
                    if(p[i] !== elm) a.push(p[i]);
                }
                return a;
            }

            var siblings = sibling(document.getElementById('first'));
            console.log(siblings);
        </script>
    </body>

</html>

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转载自www.cnblogs.com/mengfangui/p/9070841.html