第 45 届国际大学生程序设计竞赛（ICPC）亚洲网上区域赛模拟赛

第 45 届国际大学生程序设计竞赛（ICPC）亚洲网上区域赛模拟赛

A Easy Equation

#include <bits/stdc++.h>

#define int ll
//#pragma GCC optimize(2)
using namespace std;
typedef long long ll;
const int maxn = 1e5 + 10;

void solve() {
    
    
    int a,b,c,d;
    cin>>a>>b>>c>>d;
    int sum=min(a+b,d),ans=0;
    for (int i = 0; i <= sum; ++i) {
    
    
        ans+=(min(a,i)-max(i-b,0ll)+1)*(min(d-i,c)+1);
    }
    cout<<ans<<"\n";
}

signed main() {
    
    
    //ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
    int _ = 1;
//    cin >> _;
    while (_--) {
    
    
        solve();
    }
    return 0;
}

B XTL’s Chessboard

#include <bits/stdc++.h>

#define int ll
//#pragma GCC optimize(2)
using namespace std;
typedef long long ll;
const int maxn = 1e5 + 10;

void solve() {
    
    
    cout<<2;
}

signed main() {
    
    
    //ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
    int _ = 1;
//    cin >> _;
    while (_--) {
    
    
        solve();
    }
    return 0;
}

D Pokemon Ultra Sun

#include <bits/stdc++.h>

#define int ll
//#pragma GCC optimize(2)
using namespace std;
typedef long long ll;
const int maxn = 3e3 + 10;

double dp[maxn][maxn];

void solve() {
    
    
    int hp1, hp2, w;
    double p;
    cin >> hp1 >> hp2 >> w >> p;
    memset(dp,0,sizeof(dp));
    for (int i = 1; i <= hp1; ++i) {
    
    
        for (int j = 1; j <= hp2; j++) {
    
    
            dp[i][j] = dp[max(0ll,i-w)][j]*(1-p) + dp[i][max(j-w,0ll)]*p+1.0;
        }
    }
    printf("%.6f\n",dp[hp1][hp2]);
}

signed main() {
    
    
    //ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
    int _ = 1;
    cin >> _;
    while (_--) {
    
    
        solve();
    }
    return 0;
}