HDU 多校对抗赛 J Time Zone

Time Zone

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 495    Accepted Submission(s): 162

Problem Description

Chiaki often participates in international competitive programming contests. The time zone becomes a big problem.
Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone  s.

 

Input

There are multiple test cases. The first line of input contains an integer  T (1≤T≤106), indicating the number of test cases. For each test case:
The first line contains two integers a, b (0≤a≤23,0≤b≤59) and a string s in the format of "UTC+X'', "UTC-X'', "UTC+X.Y'', or "UTC-X.Y'' (0≤X,X.Y≤14,0≤Y≤9).

 

Output

For each test, output the time in the format of  hh:mm (24-hour clock).

 

Sample Input

3 11 11 UTC+8 11 12 UTC+9 11 23 UTC+0

 

Sample Output

11:11 12:12 03:23

 

Source

2018 Multi-University Training Contest 1

 

 

题意：北京标准时间是UTC+8

现在给出标准的北京时间和别的地方的时区

要求别的地方的当前时间

模拟题：

注意细节：1 会有浮点误差，所以把小数位拿出来单独计算

　　　　　2注意当h小于0的时候，要转换成前一天的时间

　　　　　3是UTC-xy时，可以当成是当前时间+16-xy的时间

代码如下

#include <cstdio>
#include <algorithm>
#include <iostream>
#include <cstring>
using namespace std;
int main(){
  int T;
  scanf("%d",&T);
 while(T--){
    int hh,mm;
    scanf("%d%d",&hh,&mm);
    char str[100];
    scanf("%s",str);
    int len=strlen(str);
    int flag=0;
    int th=0;
    int tm=0;
    if(str[3]=='+'){
      for(int i=4;i<len;i++){
        if(str[i]=='.'){
          flag=i;
          break;
        }
        th=th*10+str[i]-'0';
      }
      if(flag!=0){
        tm=str[flag+1]-'0';
        mm+=((tm*60)/10);
        if(mm>=60){
          mm-=60;
          th++;
        }
      }
      hh+=(th-8);
      if(hh>=24) hh-=24;
      if(hh<0) hh+=24;
      if(hh<10) cout<<"0"; //前导零
      cout<<hh<<":";
      if(mm<10) cout<<"0";
      cout<<mm<<endl;
    }else {
      int tth=0;
      int th=16;
      for(int i=4;i<len;i++){
        if(str[i]=='.'){
          flag=i;
          break;
        }
        tth=tth*10+str[i]-'0';
      }
      th-=tth;
      if(flag!=0){
        tm=str[flag+1]-'0';
        mm-=((tm*60)/10);
        if(mm<0){
          mm+=60;
          th--;
        }
      }
      hh+=th;
      if(hh>=24) hh-=24;
      if(hh<10) printf("0");
      printf("%d:",hh);
      if(mm<10) printf("0");
      printf("%d\n",mm);
        }
  }
  return 0;
}
/*
01 14 UTC+2.6
19:50
*/

View Code