Time Zone
@ J
Chiaki often participates in international competitive programming contests. The time zone becomes a big problem.
Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone s.
Input
There are multiple test cases. The first line of input contains an integer T (1≤T≤106), indicating the number of test cases. For each test case:
The first line contains two integers a, b (0≤a≤23,0≤b≤59) and a string s in the format of “UTC+X”, “UTC-X”, “UTC+X.Y”, or “UTC-X.Y” (0≤X,X.Y≤14,0≤Y≤9).
Output
For each test, output the time in the format of hh:mm (24-hour clock).
Sample Input
3
11 11 UTC+8
11 12 UTC+9
11 23 UTC+0
Sample Output
11:11
12:12
03:23
输入一个时间，然后把这个时间换算成那个时区的时间，我们这个时区规定为+8区。
#include <iostream>
#include <cstring>
#include <string>
using namespace std;
int main()
{
std::ios::sync_with_stdio(false);
int T;
while(cin>>T){
while (T--) {
int a,b,n = 0,m = 0 ;
string s;
cin>>a>>b>>s;
//cout<<s.size()<<endl;
if(s.size()==5)
{
n=s[4]-'0';
}
else if(s.size()==6)
{
n=s[4]-'0';
n=n*10+(s[5]-'0');
}
else if(s.size()==7)
{
n=s[4]-'0';
m=s[6]-'0';
m=m*6;
}
else if(s.size()==8)
{
n=s[4]-'0';
n=n*10+(s[5]-'0');
m=s[7]-'0';
m=m*6;
}
//cout<<n<<" "<<m<<endl;
if(s[3]=='+')
{
n=n-8;
if(n<0&&m!=0)
{
n++;
b=b-(60-m);
if(b<0) {
b+=60;
n--;
}
}
else if(m!=0)
{
b=b+m;
if(b>=60)
{
b%=60;
n++;
}
}
//cout<<n<<endl;
a=a+n;
if(a<0)a+=24;
else a%=24;
}
else
{
n = n + 8;
if(m!=0)
{
b-=m;
if(b<0)
{
a--;
b+=60;
}
}
a = a-n;
while (a<0) {
a+=24;
}
}
if(a<10)
{
if(b<10) cout<<"0"<<a<<":0"<<b<<endl;
else cout<<"0"<<a<<":"<<b<<endl;
}
else
{
if(b<10) cout<<a<<":0"<<b<<endl;
else cout<<a<<":"<<b<<endl;
}
}
}
return 0;
}