import numpy as np
def L1(yhat,y):
loss=np.sum(np.abs(y-yhat))
return loss
def L2(yhat,y):
loss=np.sum(np.power((y-yhat),2))
return loss
yhat = np.array([.9, 0.2, 0.1, .4, .9])
y = np.array([1, 0, 0, 1, 1])
print("L1 = " + str(L1(yhat,y)))
print("L2 = " + str(L2(yhat,y)))
Loss函数
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转载自blog.csdn.net/smoggyxhdz/article/details/81409357
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