HRBUST 2374 Lcm functions

http://acm.hrbust.edu.cn/index.php?m=ProblemSet&a=showProblem&problem_id=2374

此题结果不必取模

#include <bits/stdc++.h>
#define ll long long
using namespace std;
const int N = 10000000;
const int MOD = 1000000007;
int prime[664580],tot;
bool nop[N+1];
int T,k;
ll ans,n;
ll fun(ll a,ll k) {
    ll s=1;
    while (k) {
        if (k&1) s=s*a%MOD;
        a=a*a%MOD;
        k>>=1;
    }
    return s;
}
int main( ) {
    for (int i=2;i<=N;++i) {
        if (!nop[i]) prime[tot++]=i;
        for (int j=0;j<tot;++j) {
            if (1ll*prime[j]*i > 1ll*N) break;
            nop[i*prime[j]]=1;
            if (i%prime[j]==0) break;
        }
    }   
    while (~scanf("%d",&T)) {
        while (T--) {
            scanf("%lld",&n);
            ans = 1;
            for (int i=0;i<tot;++i) {
                if (n==1ll) break;  
                if (n%prime[i]!= 0) continue;
                k=0;
                while (n%prime[i]==0) {
                    k++;
                    n/=prime[i];
                }
                ans = ans*(k+k+1);
            }
                        if (n>1) ans*=3;
            //ans = ans * fun(2,MOD-2) % MOD;
            //printf("%lld\n",ans*fun(2,MOD-2)%MOD);
            ans++;
            ans = ans / 2;
            printf("%lld\n",ans);
        }
    }

    return 0;
}

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转载自blog.csdn.net/ACM2017/article/details/79700331
lcm