模拟实现C语言库函数memmove

memmove
(功能)Moves one buffer to another.

(函数参数)void *memmove( void *dest, const void *src, size_t count );

(返回值)memmove returns the value of dest.

#include<windows.h>
#include<assert.h>
void* my_memmove(void* dest,const void* str, size_t sz)
{
    assert(dest != NULL);
    assert(str != NULL);
    void* ret = dest;
    if (dest < str)
    {
        while (sz--)
        {
            *(char*)dest = *(char*)str;
            dest = (char*)dest + 1;
            str = (char*)str + 1;
        }
    }
    else
    {
        while (sz--)
        {
            *((char*)dest+sz) = *((char*)str+sz);//代码的巧妙之处,同过sz的--实现了,指针的变动
        }
    }
    return ret;
}
int main()
{
    int arr[9] = {1,2,3,4,5,6,7,8,9};
    my_memmove(arr,arr+2, 4 * sizeof(arr[0]));
    system("pause");
    return 0;
}

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转载自blog.csdn.net/aixintianshideshouhu/article/details/81230015