LeetCode专题:88. Merge Sorted Array

88. Merge Sorted Array

Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
The number of elements initialized in nums1 and nums2 are m and n respectively.
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
Example:
Input:
nums1 = [1,2,3,0,0,0], m = 3
nums2 = [2,5,6],       n = 3

Output: [1,2,2,3,5,6]

解答

import java.util.Arrays;

/**
  *类似于归并排序,会归并排序的童靴应该没毛病
  */
public class MergeSortedArray {

    public static void merge(int[] nums1, int m, int[] nums2, int n) {
        int p1 = 0; //指针1,记录nums1对应的下标
        int p2 = 0; //指针2,记录nums2对应的下标
        int [] arr = new int[n+m];
        int i=0; //指向arr
        while(p1 < m && p2 < n){ //p1 或者p2 走到末端剩下的元素直接放入arr
            arr[i++] = nums1[p1] < nums2[p2] ? nums1[p1++] : nums2[p2++];  //p1、p2指针下的元数放入arr
        }
        while (p1 < m){ //p2走到头把nums1剩下的元素放入arr
           arr[i++] = nums1[p1++];
        }
        while (p2 < n){ //p1走到头把nums2剩下的元素放入arr
            arr[i++] = nums2[p2++];
        }
        System.out.println(Arrays.toString(arr));
    }

    public static void main(String[] args) {
             int[] nums1={1,2,3,0,0,0};
             int[] nums2={2,5,6};
        merge(nums1,3,nums2,3);
    }
}

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转载自blog.csdn.net/yu0_zhang0/article/details/81749623