【python3】leetcode 88. Merge Sorted Array （easy）

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 88. Merge Sorted Array （easy）

Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:

• The number of elements initialized in nums1 and nums2 are m and n respectively.
• You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.

Example:

Input:
nums1 = [1,2,3,0,0,0], m = 3
nums2 = [2,5,6],       n = 3

Output: [1,2,2,3,5,6]

1 记录一个贼蠢的办法

class Solution:
    def merge(self, nums1, m, nums2, n):
        """
        :type nums1: List[int]
        :type m: int
        :type nums2: List[int]
        :type n: int
        :rtype: void Do not return anything, modify nums1 in-place instead.
        """
        nums1[m:(m+n)] = nums2
        nums = nums1[0:(m+n)]
        nums.sort()
        nums1[0:(m+n)] = nums

Runtime: 40 ms, faster than 70.04% of Python3 

1.2 蠢办法的稍微改进

class Solution:
    def merge(self, nums1, m, nums2, n):
        """
        :type nums1: List[int]
        :type m: int
        :type nums2: List[int]
        :type n: int
        :rtype: void Do not return anything, modify nums1 in-place instead.
        """
        nums1[m:(m+n)] = nums2
        nums1[0:(m+n)] =  sorted(nums1[0:(m+n)])

Runtime: 36 ms, faster than 99.90% of Python3

注意1 切片返回new obj，

      2 list.sort() 返回none