❤leetcode,python2❤给定一个 n × n 的二维矩阵表示一个图像。 将图像顺时针旋转 90 度。

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class Solution(object):
    def rotate(self, matrix):
        """
        :type matrix: List[List[int]]
        :rtype: void Do not return anything, modify matrix in-place instead.
        """
        n = len(matrix)
        for i in range(n/2):
            for j in range(i,n-i-1):
                tmp = matrix[i][j]
                print tmp
                matrix[i][j]=matrix[n-j-1][i]
                matrix[j][n-i-1],tmp = tmp,matrix[j][n-i-1]
                matrix[n-i-1][n-j-1],tmp = tmp,matrix[n-i-1][n-j-1]
                matrix[n-j-1][i]=tmp

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转载自blog.csdn.net/qq_22795513/article/details/80636531