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- problem link:http://codeforces.com/contest/1027/problem/C
先有下面的关系:
很明显只要a和b足够接近就可以了。AC code:
#include<bits/stdc++.h>
using namespace std;
const int N=1e6+6;
double ans=1e18,pre;
int s[N],n,i,j,ans1,ans2;
int main(){
ios::sync_with_stdio(false);cin.tie(0);
int T;cin>>T;
while(T--){
cin>>n;
for(i=1;i<=n;i++)cin>>s[i];
sort(s+1,s+1+n);
for(i=1,pre=-1;i<=n;i=j){
for(j=i;s[j]==s[i]&&j<=n;j++);
if(j-i>=4){ans=2;ans1=s[i];ans2=s[i];break;}
if(j-i>=2&&pre>0&&pre/s[i]+s[i]/pre<ans){
ans=pre/s[i]+s[i]/pre;
ans1=pre;ans2=s[i];
}
if(j-i>=2)pre=s[i];
}
cout<<ans1<<" "<<ans1<<" "<<ans2<<" "<<ans2<<endl;
ans=1e18;
}
}