求旋转数组中最小元素问题

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#include <stdio.h>
#include <iostream>
#include <vector>
using namespace std;

int get_min(vector<int> & arr){
    unsigned long length = arr.size();
    int min = arr[0];
    for (int i = 1; i< length ;i++)
    {
        if(arr[i] < min)
            min = arr[i];
    }
    return min;
}

int binary_min(vector<int> & arr){
    unsigned long begin = 0;
    int result = -99999;
    unsigned long middle;
    unsigned long end   = arr.size() - 1;
    if (arr.size() == 1){
        return -1;
    }
    while(begin<end)
    {
        if(begin + 1 == end)
        {
            result = arr[end];
            return result;
        }
        middle = (begin + end) / 2;
        if(arr[middle]==arr[begin] && arr[middle] == arr[end])
        {
            return get_min(arr);
        }
        if(arr[middle] >= arr[begin]){
            begin = middle;
        }
        else{
            end = middle;
        }
        
    }
    return result;
}

int main(){
    vector<int> node_vec({2,3,4,5,1,2});
    cout<<binary_min(node_vec);

}

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转载自blog.csdn.net/tongjinrui/article/details/80495316
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