Description
The cold and flu season is here.John is worried about his cow. In order to monitor the situation of his cow,he do some inspecting everyday,and record the “health rate” for each cow.The “health rate” is a integer which can show the cow’s health condition.The higher a cow’s health rate is ,the healthier the cow is.What’s more,the doctor told John that the k-th small health rate is dangerous.Because the doctor thought there are at most k healthy cows. So John has to find out which number is the k-th small.Can you help him?
Input
Input contains multiple test cases.
The first line contains two integers n,k (1 ≤ n ≤ 1000000,1<=k<=n) — the number of cows and dangerous number. The second line contains n integers,and the i-th integer ai(-10000<=ai<=10000) is the i-th cow’s health rate
Output
Output a single line with the k-th small health rate.
Sample Input
2 1 3 2 5 2 -1 0 -2 5 3
Sample Output
2 -1
Hint
给一串数字,求第K大的,水题,粗暴的方式是用STL的sort函数,然后直接输出第K个。
但这个题用桶排序做更优,一个数字一个坑,然后从左到右扫一遍就行了。
#include <cstdio>
#include <cstring>
#define MAXN 10000
int n,k;
int numberBucket[MAXN*2+5];
int main(){
while(scanf("%d%d",&n,&k)>0){
memset(numberBucket,0, sizeof(numberBucket));
while(n--){
int tempNum;
scanf("%d",&tempNum);
numberBucket[tempNum+MAXN]++;
}
for(int i=0;i<MAXN*2+5;i++)
{
k-=numberBucket[i];
if(k<=0){
printf("%d\n",i-MAXN);
break;
}
}
}
return 0;
}