leetcode-7. 反转整数

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/**
 * @param {number} x
 * @return {number}
 */
var reverse = function(x) {
    let r = 0;
    let res = [];
    while(x!=0){
        r = x%10;
        //res = res*10+r;
        res.push(r);
        x = (x/10)|0;
    }
    res = res.reduce((prev,curr)=>prev*10+curr,0);
    //Math.pow(2,31)等于2147483648
    return (res<-2147483648||res>2147483647)?0:res;
};