Gym - 101480D -Digit Division (思路)

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链接:

https://vjudge.net/contest/269397#problem/D

题意:

给出n位数,和一个数m,问有多少种切割方法,使得n切割出来的数都能被m整除

思路:

如果两部分都能被m整除,那么和起来一定也能

#include <bits/stdc++.h>
using namespace std;
typedef long long  ll;
const ll mod = 1e9+7;
const int maxn = 3e5+5;
char a[maxn];
ll qpow(ll x,ll m)
{
    ll ans = 1;
    while(m)
    {
        if(m&1)
        {
            ans*=x;
            ans %= mod;
        }
        x*=x;
        x%=mod;
        m/=2;
    }
    return ans;
}
int main()
{
    ll n,m,num = 0;
    cin>>n>>m;
    cin>>a;
    ll x = 0;
    for(int i = 0; i < n; i ++)
    {
        x*=10;
        x +=a[i] - '0';
        x%=m;
        if(x == 0) num ++;
    }
    ll ans ;
    if(x == 0)
        ans = qpow(2,num-1);
    else
        ans = 0;
    cout<<ans<<endl;
    return 0;
}

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转载自blog.csdn.net/Healer66/article/details/83932086