Time limit：2000 ms
Memory limit：262144 kB
Problem Description
Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:
deletes all the vowels,
inserts a character “.” before each consonant,
replaces all uppercase consonants with corresponding lowercase ones.
Vowels are letters “A”, “O”, “Y”, “E”, “U”, “I”, and the rest are consonants. The program’s input is exactly one string, it should return the output as a single string, resulting after the program’s processing the initial string.
Help Petya cope with this easy task.
Input
The first line represents input string of Petya’s program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive.
Output
Print the resulting string. It is guaranteed that this string is not empty.
问题链接：[https://vjudge.net/problem/CodeForces-118A]
问题简述：输入一串英文，删除其中AOYEUI和aoyeui，并且将所有大写英文变成小写，然后在每个字母前面加个.
问题分析：先去掉AOYEUI和aoyeui去掉，然后再把大写变为小写，之后输出结果。
AC通过的C语言程序如下：
#include<iostream>
#include<cstring>
using namespace std;
int main()
{
char a[201],len;
cin >> a;
len = strlen(a);
for (int i = 0; i < len; i++)
{
if (a[i] >= 65 && a[i] <= 90 && a[i] != 65 && a[i] != 69 && a[i] != 73 && a[i] != 79 && a[i] != 85&&a[i]!=89)
{
a[i] =a[i]+32;
cout << "." << a[i];
}
else if (a[i] >= 97 && a[i] <= 122 && a[i] != 97 && a[i] != 101 && a[i] != 105 && a[i] != 111 && a[i] != 117&&a[i]!=121)
cout << "." << a[i];
}
}