mysql 日期相减,获取天数

查询系统当前时间,不带时分秒,如:2018-11-02==>SELECT CURDATE();

日期相减函数,获取天数:datediff(CURDATE(), '2018-01-01')

下面一个demo:


SELECT 
CASE 
WHEN datediff(CURDATE(), a.year_for_car) < 180 THEN '6个月以下'
WHEN 180<= datediff(CURDATE(), a.year_for_car) AND datediff(CURDATE(), a.year_for_car) <= 365 THEN '6~12个月'
WHEN 365<= datediff(CURDATE(), a.year_for_car) AND datediff(CURDATE(), a.year_for_car) <= 730 THEN '1~2年'
WHEN 730<= datediff(CURDATE(), a.year_for_car) AND datediff(CURDATE(), a.year_for_car) <= 1095 THEN '2~3年'
WHEN 1095<= datediff(CURDATE(), a.year_for_car) THEN '3年以上'
ELSE 0
END as abc
FROM table_a a;

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转载自blog.csdn.net/wang20y8/article/details/83657614
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