经典手眼标定算法之Tsai-Lenz

文章转载自：经典手眼标定算法之Tsai-Lenz的OpenCV实现 ：http://blog.csdn.net/YunlinWang/article/details/51622143

本文主要是讲解经典手眼标定问题中的TSAI-LENZ 文献方法，参考文献为“A New Technique for Fully Autonomous and Efficient 3D Robotics Hand/Eye Calibration”，并且实现了基于OpenCV的C++代码程序，code可去CSDN资源下载，MATLAB版本作者为苏黎世理工的Christian Wengert，也可在此处下载。

void Tsai_HandEye(Mat Hcg, vector<Mat> Hgij, vector<Mat> Hcij)
{
    CV_Assert(Hgij.size() == Hcij.size());
    int nStatus = Hgij.size();

    Mat Rgij(3, 3, CV_64FC1);
    Mat Rcij(3, 3, CV_64FC1);

    Mat rgij(3, 1, CV_64FC1);
    Mat rcij(3, 1, CV_64FC1);

    double theta_gij;
    double theta_cij;

    Mat rngij(3, 1, CV_64FC1);
    Mat rncij(3, 1, CV_64FC1);

    Mat Pgij(3, 1, CV_64FC1);
    Mat Pcij(3, 1, CV_64FC1);

    Mat tempA(3, 3, CV_64FC1);
    Mat tempb(3, 1, CV_64FC1);

    Mat A;
    Mat b;
    Mat pinA;

    Mat Pcg_prime(3, 1, CV_64FC1);
    Mat Pcg(3, 1, CV_64FC1);
    Mat PcgTrs(1, 3, CV_64FC1);

    Mat Rcg(3, 3, CV_64FC1);
    Mat eyeM = Mat::eye(3, 3, CV_64FC1);

    Mat Tgij(3, 1, CV_64FC1);
    Mat Tcij(3, 1, CV_64FC1);

    Mat tempAA(3, 3, CV_64FC1);
    Mat tempbb(3, 1, CV_64FC1);

    Mat AA;
    Mat bb;
    Mat pinAA;

    Mat Tcg(3, 1, CV_64FC1);

    for (int i = 0; i < nStatus; i++)
    {
        Hgij[i](Rect(0, 0, 3, 3)).copyTo(Rgij);
        Hcij[i](Rect(0, 0, 3, 3)).copyTo(Rcij);

        Rodrigues(Rgij, rgij);
        Rodrigues(Rcij, rcij);

        theta_gij = norm(rgij);
        theta_cij = norm(rcij);

        rngij = rgij / theta_gij;
        rncij = rcij / theta_cij;

        Pgij = 2 * sin(theta_gij / 2)*rngij;
        Pcij = 2 * sin(theta_cij / 2)*rncij;

        tempA = skew(Pgij + Pcij);
        tempb = Pcij - Pgij;

        A.push_back(tempA);
        b.push_back(tempb);
    }

    //Compute rotation
    invert(A, pinA, DECOMP_SVD);

    Pcg_prime = pinA * b;
    Pcg = 2 * Pcg_prime / sqrt(1 + norm(Pcg_prime) * norm(Pcg_prime));
    PcgTrs = Pcg.t();   
    Rcg = (1 - norm(Pcg) * norm(Pcg) / 2) * eyeM + 0.5 * (Pcg * PcgTrs + sqrt(4 - norm(Pcg)*norm(Pcg))*skew(Pcg));

    //Computer Translation 
    for (int i = 0; i < nStatus; i++)
    {
        Hgij[i](Rect(0, 0, 3, 3)).copyTo(Rgij);
        Hcij[i](Rect(0, 0, 3, 3)).copyTo(Rcij);
        Hgij[i](Rect(3, 0, 1, 3)).copyTo(Tgij);
        Hcij[i](Rect(3, 0, 1, 3)).copyTo(Tcij);


        tempAA = Rgij - eyeM;
        tempbb = Rcg * Tcij - Tgij;

        AA.push_back(tempAA);
        bb.push_back(tempbb);
    }

    invert(AA, pinAA, DECOMP_SVD);
    Tcg = pinAA * bb;

    Rcg.copyTo(Hcg(Rect(0, 0, 3, 3)));
    Tcg.copyTo(Hcg(Rect(3, 0, 1, 3)));
    Hcg.at<double>(3, 0) = 0.0;
    Hcg.at<double>(3, 1) = 0.0;
    Hcg.at<double>(3, 2) = 0.0;
    Hcg.at<double>(3, 3) = 1.0;

}