【python】点坐标旋转

 实现了某点按照中心点(n/2, m/2)旋转

def rotatecordiate(angle,rect):
    angle=angle*math.pi/180
    n=1600
    m=1200
    def onepoint(x,y):
        # X = x*math.cos(angle) - y*math.sin(angle)-0.5*n*math.cos(angle)+0.5*m*math.sin(angle)+0.5*n
        # Y = y*math.cos(angle) + x*math.sin(angle)-0.5*n*math.sin(angle)-0.5*m*math.cos(angle)+0.5*m
        X = x * math.cos(angle) - y * math.sin(angle) - 0.5 * n * math.cos(angle) + 0.5 * m * math.sin(angle) + 0.5 * n
        Y = y * math.cos(angle) + x * math.sin(angle) - 0.5 * n * math.sin(angle) - 0.5 * m * math.cos(angle) + 0.5 * m
        return [int(X),int(Y)]
    newrect=[]
    for i in range(4):
        point=onepoint(rect[i*2],rect[i*2+1])
        newrect.extend(point)
    newrect.extend([1])
    print(newrect)
    return newrect

参考：https://blog.csdn.net/u011489887/article/details/81014623