python 获取两个时间段之间的每一天的list(月日为个位数的情况，包含0/不包含0)

1. 需求：获取两个时间段之间的每一天的list(月日为个位数的情况,包含0)

import pandas as pd
import datetime, time


def deal(begin_date, end_date):
    date_list = []
    begin_date = datetime.datetime.strptime(begin_date, "%Y.%m.%d")
    end_date = datetime.datetime.strptime(end_date, "%Y.%m.%d")
    while begin_date <= end_date:
        date_str = begin_date.strftime("%Y.%m.%d")
        date_list.append(date_str)
        begin_date += datetime.timedelta(days=1)
    print(date_list)
    return date_list


if __name__ == '__main__':
    deal('2018.2.2', '2018.2.5')

运行结果：

['2018.02.02', '2018.02.03', '2018.02.04', '2018.02.05']

2. 需求：获取两个时间段之间的每一天的list(月日为个位数的情况,不包含0)

def deal(begin_date, end_date):
    date_list = []
    begin_date = datetime.datetime.strptime(begin_date, "%Y.%m.%d")
    end_date = datetime.datetime.strptime(end_date, "%Y.%m.%d")
    while begin_date <= end_date:
        date_str = str(begin_date.year) + '.' + str(begin_date.month) + '.' + str(begin_date.day)
        date_list.append(date_str)
        begin_date += datetime.timedelta(days=1)
    print(date_list)
    return date_list


if __name__ == '__main__':
    deal('2018.2.2', '2018.2.5')

运行结果：

['2018.2.2', '2018.2.3', '2018.2.4', '2018.2.5']