常见排列组合公式

1 : C [ n ] [ m ] = f [ n ] / f [ m ] / f [ n m ] ( f [ i ] i ) 1:C[n][m] = f[n] / f[m] / f[n-m] (f[i]为i的阶乘)
2 : A [ n ] [ m ] = f [ n ] / f [ m ] 2:A[n][m] = f[n] / f[m]
3 : C [ n ] [ 0 ] + C [ n ] [ 1 ] + C [ n ] [ 2 ] + . . . C [ n ] [ n ] = 2 n 3:C[n][0]+C[n][1]+C[n][2]+...C[n][n] = 2^n
4 : C [ n ] [ 0 ] + C [ n ] [ 2 ] + C [ n ] [ 4 ] + . . . = C [ n ] [ 1 ] + C [ n ] [ 3 ] + C [ n ] [ 5 ] = 2 n 1 4:C[n][0] + C[n][2] + C[n][4] + ... = C[n][1] + C[n][3] + C[n][5] = 2^{n-1}
5 : 0 C [ n ] [ 0 ] + 1 C [ n ] [ 1 ] + 2 C [ n ] [ 2 ] + . . . n C [ n ] [ n ] = n 2 n 1 5:0*C[n][0]+1*C[n][1]+2*C[n][2]+...n*C[n][n] = n*2^{n-1}

5 证明5式:
( 1 + x ) n = C [ n ] [ 0 ] + x C [ n ] [ 1 ] + x 2 C [ n ] [ 2 ] + x 3 C [ n ] [ 3 ] + . . . + x n C [ n ] [ n ] (1+x)^n = C[n][0] + xC[n][1] + x^2C[n][2] + x^3C[n][3] + ... + x^nC[n][n]
x = 1 两边求导后将x=1带入即可

发布了132 篇原创文章 · 获赞 6 · 访问量 7925

猜你喜欢

转载自blog.csdn.net/weixin_44316314/article/details/104882367
今日推荐