Problem Description The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.
Input Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 … nm where m is the number of integers in the set and n1 … nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.
Output For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.
Sample Input
2
3 5 7 15
6 4 10296 936 1287 792 1
Sample Output
105
10296
#include"iostream"
using namespace std;
int gcd(long long a,long long b)
{
if(a%b==0)
return b;
else
return gcd(b,a%b);
}//求最大公约数
int main()
{
int x,n,m;
long long c;
while (cin>>n)
{
for (int i=0;i<n;i++)
{
c=1;
cin>>m;
for (int j=0;j<m;j++)
{
cin>>x;
c=x*c/gcd(c,x);//求最小公倍数
}
cout<<c<<endl;
}
}
return 0;
}