使用C++实现一个矩形类根据矩形左下角和右上角两个坐标求出面积

题目:

设计一个Rectangle类,属性为矩形的左下角与右上角两个坐标,计算矩形面积。

题目分析:

 

可知根据题目要求需先定义一个点类用于存储两个点的坐标

class Point2
{
public:
	int x;
	int y;

	void setPoint2(int xx, int yy)
	{
		this->x = xx;
		this->y = yy;
	}

};

然后定义一个Rectangle类

class Rectangle
{
public:
	Point2 rightPoint;
	Point2 leftPoint;
	Rectangle(int rx, int ry, int lx, int ly)
	{
		rightPoint.setPoint2(rx, ry);
		leftPoint.setPoint2(lx, ly);
	}

	int Area()
	{
		int length = abs(rightPoint.x - leftPoint.x);
		int width = abs(rightPoint.y - leftPoint.y);
		return length * width;
	}
};

完整代码如下

#include <iostream>
using namespace std;

class Point2
{
public:
	int x;
	int y;

	void setPoint2(int xx, int yy)
	{
		this->x = xx;
		this->y = yy;
	}

};

class Rectangle
{
public:
	Point2 rightPoint;
	Point2 leftPoint;
	Rectangle(int rx, int ry, int lx, int ly)
	{
		rightPoint.setPoint2(rx, ry);
		leftPoint.setPoint2(lx, ly);
	}

	int Area()
	{
		int length = abs(rightPoint.x - leftPoint.x);
		int width = abs(rightPoint.y - leftPoint.y);
		return length * width;
	}
};

int main()
{
	Rectangle r1(0,4,4,0);

	cout << "面积为:" << r1.Area() << endl;

	return 0;
}
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