【哈希-中等】648. 单词替换(暴力解法+前缀哈希+前缀树)

【题目】
在英语中,我们有一个叫做 词根(root)的概念,它可以跟着其他一些词组成另一个较长的单词——我们称这个词为 继承词(successor)。例如,词根an,跟随着单词 other(其他),可以形成新的单词 another(另一个)。
现在,给定一个由许多词根组成的词典和一个句子。你需要将句子中的所有继承词用词根替换掉。如果继承词有许多可以形成它的词根,则用最短的词根替换它。
你需要输出替换之后的句子。
【示例 1】
输入:dictionary = [“cat”,“bat”,“rat”], sentence = “the cattle was rattled by the battery”
输出:“the cat was rat by the bat”
【示例 2】
输入:dictionary = [“a”,“b”,“c”], sentence = “aadsfasf absbs bbab cadsfafs”
输出:“a a b c”
【示例 3】
输入:dictionary = [“a”, “aa”, “aaa”, “aaaa”], sentence = “a aa a aaaa aaa aaa aaa aaaaaa bbb baba ababa”
输出:“a a a a a a a a bbb baba a”
【示例 4】
输入:dictionary = [“catt”,“cat”,“bat”,“rat”], sentence = “the cattle was rattled by the battery”
输出:“the cat was rat by the bat”
【示例 5】
输入:dictionary = [“ac”,“ab”], sentence = “it is abnormal that this solution is accepted”
输出:“it is ab that this solution is ac”
【提示】
1 <= dictionary.length <= 1000
1 <= dictionary[i].length <= 100
dictionary[i] 仅由小写字母组成。
1 <= sentence.length <= 10^6
sentence 仅由小写字母和空格组成。
sentence 中单词的总量在范围 [1, 1000] 内。
sentence 中每个单词的长度在范围 [1, 1000] 内。
sentence 中单词之间由一个空格隔开。
sentence 没有前导或尾随空格。
【代码】
【Python】
【方法1】

class Solution:
    def replaceWords(self, dictionary: List[str], sentence: str) -> str:
        sen_list=sentence.split(" ")
        for i in range(len(sen_list)):
            for d in dictionary:
                if sen_list[i].find(d)==0:
                    sen_list[i]=d
        return " ".join(sen_list)

【方法2】前缀哈希

class Solution:
    def replaceWords(self, roots, sentence):
        rootset = set(roots)
        def replace(word):
            for i in range(1, len(word)):
                if word[:i] in rootset:
                    return word[:i]
            return word
        return " ".join(map(replace, sentence.split()))

【方法3】前缀树

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转载自blog.csdn.net/kz_java/article/details/114763012