杭电OJ 1003 求和最大连续子序列

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;

int main()
{
	int T;
	cin >> T;
	for (int i = 0; i < T; i++)
	{
		int n;
		cin >> n;
		vector<int> dp(n), a(n),N(n);
		for (int j = 0; j < n; j++)
			cin >> a[j];
		dp[0] = a[0];
		N[0] = 0;
		for (int j = 1; j < n; j++)
		{
			if (a[j]>dp[j - 1] + a[j])
			{
				N[j] = 0;
				dp[j] = a[j];
			}
			else
			{
				N[j] = N[j - 1] + 1;
				dp[j] = dp[j - 1] + a[j];
			}
		}
		int maxD = dp[0];
		int endA = 0;
		for (int j = 0; j < n; j++)
			if (maxD < dp[j])
			{
			maxD = dp[j];
			endA = j;
			}
		cout << "Case " << i + 1 << ":" << endl;
		cout << maxD << " "<<endA-N[endA]+1<<" "<<endA+1<<endl;
		if (i != T - 1)
			cout << endl;

	}
	return 0;
}

猜你喜欢

转载自blog.csdn.net/fuwu4087/article/details/80715270