Time Zone
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 677 Accepted Submission(s): 227
Problem Description
Chiaki often participates in international competitive programming contests. The time zone becomes a big problem.
Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone s.
Input
There are multiple test cases. The first line of input contains an integer T (1≤T≤106), indicating the number of test cases. For each test case:
The first line contains two integers a, b (0≤a≤23,0≤b≤59) and a string s in the format of "UTC+X'', "UTC-X'', "UTC+X.Y'', or "UTC-X.Y'' (0≤X,X.Y≤14,0≤Y≤9).
Output
For each test, output the time in the format of hh:mm (24-hour clock).
Sample Input
3
11 11 UTC+8
11 12 UTC+9
11 23 UTC+0
Sample Output
11:11
12:12
03:23
Source
2018 Multi-University Training Contest 1
#include <iostream>
#include <cstdio>
#include <cmath>
#define LL long long
using namespace std;
int around(float x)
{
int cnt = 1;
if(x<0) cnt = -cnt;
if(abs(x)-abs((int)x) > 0.5)
return (int)x+cnt;
return (int)x;
}
int main()
{
int t, m, h;
float x;
char ch;
string str;
scanf("%d", &t);
while(t --)
{
scanf("%d%d", &h, &m);
getchar();
scanf("UTC%c%f", &ch, &x);
if(ch=='-') x=-x;
x-=8;
//printf("%d %f %f\n", m, (x-(int)x), (x-(int)x)*60);
m+=around((x-(int)x)*60);
h+=(int)x;
if(m>=60){m-=60;h++;}
if(m<0){m+=60;h--;}
if(h>=24){h-=24;}
if(h<0) {h+=24;}
if(h<10) printf("0");
printf("%d:", h);
if(m<10) printf("0");
printf("%d\n", m);
}
}