c++水仙花数(二)

#include “stdafx.h”
#include
int lifang(int);
using namespace std;

int main()
{
int i;
while (1 == 1) {
cin >> i;
if (i >= 100 && i <= 1000)
{
if (lifang(i / 100) + lifang(i % 10) + lifang(i % 100 / 10) == i)
{
cout << i << “是一个水仙花数!” << endl;
return true;
}
else
cout << i << “不是水仙花数!” << endl;
}
else
cout << “请重新赋值!”<<endl;
}
return 0;
}
int lifang(int n)
{
return nnn;
}

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转载自blog.csdn.net/weixin_43210805/article/details/82764930