c++水仙花数

#include “stdafx.h”
#include
int lifang(int);
using namespace std;

int main()
{
int i;
for (i= 100;i<= 999;i++)
{
if (lifang(i / 100) + lifang(i % 10) + lifang(i % 100 / 10) == i)
cout << i << endl;
}
return 0;
}
int lifang(int n)
{
return nnn;
}
//lifang(i / 100) + lifang(i % 10) + lifang(i % 100 / 10) == i

猜你喜欢

转载自blog.csdn.net/weixin_43210805/article/details/82764798