- 题目:
1058 A+B in Hogwarts (20 分)
If you are a fan of Harry Potter, you would know the world of magic has its own currency system – as Hagrid explained it to Harry, “Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it’s easy enough.” Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
- 解题思路
用tag记录是否进位。若进位,则tag =1;否则tag = 0;
代码实现:
#include <iostream>
#include <cstdio>
using namespace std;
struct Node{
int a;
int b;
int c;
}A,B, res;
int main()
{
scanf("%d.%d.%d",&A.a, &A.b, &A.c);
scanf("%d.%d.%d",&B.a, &B.b, &B.c);
int tag = 0;
if(A.c + B.c < 29){
res.c = A.c + B.c;
tag = 0;
} else {
res.c = (A.c + B.c) %29;
tag =1;
}
if(A.b + B.b + tag < 17){
res.b = A.b + B.b + tag;
tag = 0;
} else {
res.b = (A.b + B.b + tag) %17;
tag = 1;
}
res.a = A.a + B.a +tag;
cout << res.a <<"." << res.b <<"." << res.c;
return 0;
}