PAT 1058 A+B in Hogwarts (20)

1058 A+B in Hogwarts (20)（20 分）

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 10^7], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

思路：

这道题真的很水啦， 就相当于第二位是17进制，第三位是29进制，意外发现第一位不用控制也可以过所有测试数据……

代码：

#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <iostream>
#include <algorithm>
#include <string>
#include <vector>
#include <queue>
#include <map>  
#include <set>
using namespace std;

int main()
{	
	int a[3],b[3];
	char c;
	cin>>a[0]>>c>>a[1]>>c>>a[2];
	cin>>b[0]>>c>>b[1]>>c>>b[2];
	a[2]=a[2]+b[2];
	a[1]+=a[2]/29;
	a[2]=a[2]%29;
	a[1]=a[1]+b[1];
	a[0]+=a[1]/17;
	a[1]=a[1]%17;
	a[0]=a[0]+b[0];
	cout<<a[0]<<"."<<a[1]<<"."<<a[2];
	return 0;
}