PAT:A1058 A+B in Hogwarts (20 分)

版权声明:本文为博主原创文章,未经博主允许不得转载。 https://blog.csdn.net/Ecloss/article/details/82664537

PAT:A1058 A+B in Hogwarts (20 分)

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and Bare given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,10​7​​], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

代码:

#include<stdio.h>

int main() {
	long long g, s, k,g1, s1, k1, temp;
	scanf("%lld.%lld.%lld %lld.%lld.%lld", &g, &s, &k, &g1, &s1, &k1);	
	temp = g*17*29 + s*29 + k + g1*17*29 + s1*29 + k1;
	printf("%lld.%lld.%lld", temp / (17*29), temp / 29 % 17, temp % 29); 
	return 0;
}

猜你喜欢

转载自blog.csdn.net/Ecloss/article/details/82664537