1058 A+B in Hogwarts （20 分)

1058 A+B in Hogwarts （20 分)

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,10​7​​], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

#include <iostream>
#include <bits/stdc++.h>
using namespace std;


int main()
{
    int a1,a2,a3,b1,b2,b3,ans1,ans2,ans3;
    char c;
    cin >>a1>>c>>a2>>c>>a3>>b1>>c>>b2>>c>>b3;
    int cc;
    ans3 = (a3+b3)%29;
    if(a3+b3>=29) cc = 1; else cc = 0;
    ans2 = (a2+b2+cc)%17;
    if(a2+b2+cc>=17) cc = 1; else cc = 0;
    ans1 = a1+b1+cc;
    printf("%d.%d.%d",ans1,ans2,ans3);
    return 0;
}