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问题 A: Fibonacci
时间限制: 1 Sec 内存限制: 32 MB
提交: 588 解决: 196
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题目描述
The Fibonacci Numbers{0,1,1,2,3,5,8,13,21,34,55...} are defined by the recurrence:
F0=0 F1=1 Fn=Fn-1+Fn-2,n>=2
Write a program to calculate the Fibonacci Numbers.
输入
Each case contains a number n and you are expected to calculate Fn.(0<=n<=30) 。
输出
For each case, print a number Fn on a separate line,which means the nth Fibonacci Number.
样例输入
1
样例输出
1
#include<iostream>
using namespace std;
typedef long long ll;
const int N=120;//太大会溢出
ll dp[N]={0};
ll F(int n){
if(n==0) return 0;
if(n==1) return 1;
if(dp[n]!=0) return dp[n];
else{
dp[n]=F(n-1)+F(n-2);
return dp[n];
}
}
int main(){
int n;
while(cin>>n){
cout<<F(n)<<endl;
}
return 0;
}