113. Path Sum II(路径和II)

原题链接:https://leetcode.com/problems/path-sum-ii/

Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.

Note: A leaf is a node with no children.

Example:

Given the below binary tree and sum = 22,

      5
     / \
    4   8
   /   / \
  11  13  4
 /  \    / \
7    2  5   1

Return:

[
   [5,4,11,2],
   [5,8,4,5]
]

思路:递归回溯。

AC 1ms 99.6% Java:

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    List<List<Integer>> ans=new ArrayList();
    public List<List<Integer>> pathSum(TreeNode root, int sum) {
        if(root==null)
            return ans;
        helper(root,sum,new ArrayList<Integer>());
        return ans;
    }
    public void helper(TreeNode root,int sum,List<Integer> list){
        if(root==null)
            return;
        int remain=sum-root.val;
        list.add(root.val);
        if(remain==0&&root.left==null&&root.right==null){
            ans.add(new ArrayList(list));
        }
        helper(root.left,remain,list);
        helper(root.right,remain,list);
        list.remove(list.size()-1);
    }
}

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转载自blog.csdn.net/God_Mood/article/details/88959010