构建二叉树

//输入某二叉树的前序遍历和中序遍历的结果,请重建出该二叉树。假设输入的前序遍历和中序遍历的结果中都不含重复的数字。例如输入前序遍历序列{1,2,4,7,3,5,6,8}和中序遍历序列{4,7,2,1,5,3,8,6},则重建二叉树并返回。

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode* reConstructBinaryTree(vector<int> pre,vector<int> vin) 
    {
        if (pre.empty())
            return NULL;
        TreeNode *head = new TreeNode(pre[0]);
        vector<int> ::iterator pos = find(vin.begin(), vin.end(), pre[0]);
        vector<int> vinleft (vin.begin(),  pos);
        vector<int> vinright(pos + 1, vin.end());
        vector<int> preleft(pre.begin()+1, pre.begin()+vinleft.size() +1);
        vector<int> preright(pre.begin()+vinleft.size() +1, pre.end());
        head->left = reConstructBinaryTree(preleft, vinleft);
        head->right = reConstructBinaryTree(preright, vinright);
        return head;
    }
};

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转载自blog.csdn.net/pynash123/article/details/88868909