double和float进行小数计算精度不够

1、float和double只能用来作科学计算或者是工程计算,但在商业计算中我们要用java.math.BigDecimal

2、注意:double 和float转换为字符串类型造成进度丢失;直接用字符串表示double 和float

3、案例:

package com.zhangwl.pg1113;

import org.junit.Test;

import java.math.BigDecimal;

/**
* @ClassName RunMain
* @Description 演示小案例
* @Author zhangwl
* @Date 2019/11/13 23:02
* @Version 1.0
**/
public class RunMain {

@Test
public void test_01() {
BigDecimal douDecMax = new BigDecimal(2.0);
BigDecimal douDecMin = new BigDecimal(1.10);
System.out.println("douDecMax - douDecMin = " + douDecMax.subtract(douDecMin));

System.out.println("********************分界线*************************");

BigDecimal strDecMax = new BigDecimal("2.0");
BigDecimal strDecMin = new BigDecimal("1.10");
System.out.println("strDecMax - strDecMin = " + strDecMax.subtract(strDecMin));
System.out.println();
}
}


运行结果:

douDecMax - douDecMin = 0.899999999999999911182158029987476766109466552734375
********************分界线*************************
strDecMax - strDecMin = 0.90

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转载自www.cnblogs.com/sico/p/11854056.html