PAT (Advanced Level) Practice1001 A+B Format (20 分)（Java实现）

Problem Description

Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where $−10^6 ≤a,b≤10^6$ . The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

代码示例（Java实现）

import java.util.Scanner;

/**
 * @author snowflake
 * @create-date 2019-07-17 23:19
 */
public class Main {

    public static void main(String[] args) {
        Scanner cin = new Scanner(System.in);
        int sum = cin.nextInt() + cin.nextInt();
        // 取出符号位
        String sign = sum < 0 ? "-" : "";
        // 将数字转化为绝对值
        sum = Math.abs(sum);
        // 三位数及其一下
        if (sum < 1000) {
            System.out.println(sign + sum);
        } else {
        	// 将数字转化为字符串
            String str = sum + "";
            StringBuilder result = new StringBuilder();
            // 从右往左进行操作，每次移动三位
            for (int i = 0; i < str.length(); i += 3) {
            	// 如果剩余的字符串还剩余三位以上
                if (i + 3 < str.length()) {
                    result.insert(0, ",").insert(0, str.substring(str.length() - i - 3, str.length() - i));
                } else {
                    result.insert(0, ",").insert(0, str.substring(0, str.length() - i));
                }
            }
            // 结果要补上符号位
            System.out.println(sign + result.substring(0, result.length() - 1));
        }
    }

}