#PAT甲级1001 A+B Format (20分)
题目:Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b
. The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
-999,991
第一题解题思路:输入int 型变量a与b,将a与b相加赋给c,如果c小于0则输出一个负号,将结果利用to-string函数变为字符串形式s,然后将该字符串逆置,用s1字符串存储答案,对于s的逆序进行遍历,每隔三个字符输出一个‘,’,若最后一个字符序号恰好为3的整数倍,则不用输出‘,’,最后将s1逆置回来,输出s1。
AC代码附上:
#include <iostream>
#include <algorithm>
using namespace std;
int main(){
int a,b,c;
string s,s1="";
cin>>a>>b;
c=a+b;
if(c<0){
cout<<"-";
c=-c;
}
s=to_string(c);
reverse(s.begin(),s.end());
for(int i=0;i<s.length();i++){
s1+=s[i];
if((i+1)%3==0&&(i!=s.length()-1)){
s1+=',';
}
}
reverse(s1.begin(),s1.end());
cout<<s1;
return 0;
}