(救济金发放)The Dole Queue(UVA - 133)(循环队列的处理)

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//循环队列
#include<iostream>
#include<cstdio>

using namespace std;

const int maxn=25;

int n,k,m,a[maxn];

int go(int p,int d,int t)
{
    while(t--){
        do{
            p=(p+d+n-1)%n+1;//此处循环条件重要
        }while(a[p]==0);
    }
    return p;
}

int main()
{
    while(scanf("%d%d%d",&n,&k,&m)==3&&n){
        for(int i=1;i<=n;i++){
            a[i]=i;
        }
        int left=n;
        int p1=n,p2=1;
        while(left){
            p1=go(p1,1,k);
            p2=go(p2,-1,m);
            printf("%3d",p1);
            left--;
            if(p2!=p1){
                printf("%3d",p2);
                left--;
            }
            a[p1]=a[p2]=0;
            if(left){
                printf(",");
            }
        }
        printf("\n");
    }
    return 0;
}

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转载自blog.csdn.net/zhouzi2018/article/details/80719435