I-Molar mass

Molar mass

Time limit: 3.000 seconds

An organic compound is any member of a large class of chemical compounds whose molecules contain carbon. Themolar mass of an organic compound is the mass of one mole of the organic compound. The molar mass of an organic compound can be computed from the standard atomic weights of the elements.

When an organic compound is given as amolecular formula, Dr. CHON wants to find its molar mass. A molecular formula, such asC3H4O3, identifies each constituent element by its chemical symbol and indicates the number of atoms of each element found in each discrete molecule of that compound. If a molecule contains more than one atom of a particular element, this quantity is indicated using a subscript after the chemical symbol.

In this problem, we assume that the molecular formula is represented by only four elements, `C' (Carbon), `H' (Hydrogen), `O' (Oxygen), and `N' (Nitrogen) without parentheses.

The following table shows that the standard atomic weights for `C', `H', `O', and `N'.

Atomic Name	Carbon	Hydrogen	Oxygen	Nitrogen
Standard Atomic Weight	12.01 g/mol	1.008 g/mol	16.00 g/mol	14.01 g/mol

For example, the molar mass of a molecular formula C6H5OH is 94.108 g/mol which is computed by 6× (12.01 g/mol) + 6 × (1.008 g/mol) + 1× (16.00 g/mol).

Given a molecular formula, write a program to compute the molar mass of the formula.

Input 

Your program is to read from standard input. The input consists of T test cases. The number of test cases T is given in the first line of the input. Each test case is given in a single line, which contains a molecular formula as a string. The chemical symbol is given by a capital letter and the length of the string is greater than 0 and less than 80. The quantity numbern which is represented after the chemical symbol would be omitted when the number is 1(2n99).

Your program is to write to standard output. Print exactly one line for each test case. The line should contain the molar mass of the given molecular formula.

4 
C 
C6H5OH 
NH2CH2COOH 
C12H22O11

12.010 
94.108 
75.070 
342.296

#include<stdio.h>
#include<string.h>
int main()
{
	double s[1000];
	s['C']=12.01;
	s['H']=1.008;
	s['O']=16.00;
	s['N']=14.01;
	char ch[1000];
	int n,count=0;
	scanf("%d",&n);
	while(n--)
	{
		scanf("%s",ch);//输入字符串
		int i=0;
		char a;
		double w=0;
		while(ch[i]!='\0')//循环遍历字符串
		{
			double sum=0;
			a=ch[i];
			i++;
			while(ch[i]>='0'&&ch[i]<='9')//判断下一位是否为数字
			{
			    sum=sum*10+ch[i]-'0';//如果数字，求出数字大小
				i++;//进行自加，便以判断下一位
			}
		    if(sum) w=w+sum*s[a];//如果有数字进行以下操作
		    else w=w+s[a];
		}
		printf("%.3lf\n",w);
	}
}