Let s(x)s(x) be sum of digits in decimal representation of positive integer xx. Given two integers nn and mm, find some positive integers aa and bb such that
- s(a)≥ns(a)≥n,
- s(b)≥ns(b)≥n,
- s(a+b)≤ms(a+b)≤m.
Input
The only line of input contain two integers nn and mm (1≤n,m≤11291≤n,m≤1129).
Output
Print two lines, one for decimal representation of aa and one for decimal representation of bb. Both numbers must not contain leading zeros and must have length no more than 22302230.
Examples
input
Copy
6 5
output
Copy
6 7
input
Copy
8 16
output
Copy
35 53
Note
In the first sample, we have n=6n=6 and m=5m=5. One valid solution is a=6a=6, b=7b=7. Indeed, we have s(a)=6≥ns(a)=6≥n and s(b)=7≥ns(b)=7≥n, and also s(a+b)=s(13)=4≤ms(a+b)=s(13)=4≤m.
这道题一开始我想着是暴力的 后来看翻译才知道数字长短在2230范围内 然后看别人的代码 然后发现这是一道思维题。。哎 自己太笨了 然后就直接上代码吧 智商需要充值了。。
#include <cstring>
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <string.h>
#include <map>
#define ll long long
using namespace std;
#define pai acos(-1,0)
int main()
{
int n,m;
cin>>n>>m;
for(int i=1;i<=2230;i++)
cout<<8;
cout<<endl;
for(int i=1;i<=2229;i++)
cout<<1;
cout<<2;
cout<<endl;
return 0;
}