牛客练习赛27 A-纸牌

版权声明:喜欢请点个大拇指,感谢各位dalao。弱弱说下,转载要出处呦 https://blog.csdn.net/qq_35786326/article/details/82813424


题目:

传送门


分析:

虽然小编才刚刚开始做牛客网,但这道题是真的很水很水,小学生水平的数论题


代码:

#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstring> 
#include<cstdlib>
#include<algorithm>
#include<set>
#include<queue>
#include<vector>
#include<map>
#include<list>
#include<ctime>
#include<iomanip>
#include<string>
#include<bitset>
#include<deque>
#include<set>
#define LL long long
#define h happy
#define ch cheap
#define XJQ 99999999
#define HSZGB 还是欠老子400块
using namespace std;
inline LL read() {
    LL d=0,f=1;char s=getchar();
    while(s<'0'||s>'9'){if(s=='-')f=-1;s=getchar();}
    while(s>='0'&&s<='9'){d=d*10+s-'0';s=getchar();}
    return d*f;
}
int main()
{
    int n=read();
    cout<<(n+1)/2;
    return 0;
}

猜你喜欢

转载自blog.csdn.net/qq_35786326/article/details/82813424