Ignatius and the Princess IV
Problem Description
"OK, you are not too bad, em... But you can never pass the next test." feng5166 says.
"I will tell you an odd number N, and then N integers. There will be a special integer among them, you have to tell me which integer is the special one after I tell you all the integers." feng5166 says.
"But what is the characteristic of the special integer?" Ignatius asks.
"The integer will appear at least (N+1)/2 times. If you can't find the right integer, I will kill the Princess, and you will be my dinner, too. Hahahaha....." feng5166 says.
Can you find the special integer for Ignatius?
Input
The input contains several test cases. Each test case contains two lines. The first line consists of an odd integer N(1<=N<=999999) which indicate the number of the integers feng5166 will tell our hero. The second line contains the N integers. The input is terminated by the end of file.
Output
For each test case, you have to output only one line which contains the special number you have found.
Sample Input
5
1 3 2 3 3
11
1 1 1 1 1 5 5 5 5 5 5
7
1 1 1 1 1 1 1
Sample Output
3 5 1
题意描述：
在n个数中找到那个出现次数大于等于（n+1）/2的那个数，由于是出现了一半以上，所以这种数最多只有一个，我用了桶排序的思想
程序代码：
#include<stdio.h>
#include<string.h>
int a[1000010];
int main()
{
int n,m,i,max;
while(scanf("%d",&n)!=EOF)
{
memset(a,0,sizeof(a));
for(i=0;i<n;i++)
{
scanf("%d",&m);
a[m]++;
if(a[m]>=(n+1)/2)
max=m;
}
printf("%d\n",max);
}
return 0;
}